# python数字转对应中文的方法总结

windows7系统，DELL G3电脑，python3.5版

python实现将阿拉伯数字转换成中文

```    1  -->  一
12   -->  一二
def num_to_char(num):
"""数字转中文"""
num=str(num)
new_str=""
num_dict={"0":u"零","1":u"一","2":u"二","3":u"三","4":u"四","5":u"五","6":u"六","7":u"七","8":u"八","9":u"九"}
listnum=list(num)
# print(listnum)
shu=[]
for i in listnum:
# print(num_dict[i])
shu.append(num_dict[i])
new_str="".join(shu)
# print(new_str)
return new_str```

```     1   -->   一
12  -->   十二
23  -->  二十三
_MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', u'十', u'十一', u'十二', u'十三', u'十四', u'十五', u'十六', u'十七',u'十八', u'十九')
_P0 = (u'', u'十', u'百', u'千',)
_S4 = 10 ** 4
def _to_chinese4(num):
assert (0 <= num and num < _S4)
if num < 20:
return _MAPPING[num]
else:
lst = []
while num >= 10:
lst.append(num % 10)
num = num / 10
lst.append(num)
c = len(lst)  # 位数
result = u''
for idx, val in enumerate(lst):
val = int(val)
if val != 0:
result += _P0[idx] + _MAPPING[val]
if idx < c - 1 and lst[idx + 1] == 0:
result += u'零'
return result[::-1]```

```#!/usr/bin/python
#-*- encoding: utf-8 -*-http://www.cppcns.com

import types

class NotIntegerError(Exception):
pass

class OutOfRangeError(Exception):
pass

_MAPPING = (u'零', u'一', u'二', u'三', u'四', u'五', u'六', u'七', u'八', u'九', )http://www.cppcns.com
_P0 = (u'', u'十', u'百', u'千', )
_S4, _S8, _S16 = 10 ** 4 , 10 ** 8, 10 ** 16
_MIN, _MAX = 0, 9999999999999999

def _to_chinese4(num):
'''转换[0, 10000)之间的阿拉伯数字
'''
assert(0 <= num and num < _S4)
if num < 10:
return _MAPPING[num]
else:
lst = [ ]
while num >= 10:
lst.append(num % 10)
num = num / 10
lst.append(num)
c = len(lst)  # 位数
result = u''

for idx, val in enumerate(lst):
if val != 0:
result += _P0[idx] + _MAPPING[val]
if idx < c - 1 and lst[idx + 1] == 0:
result += u'零'

return result[::-1].replace(u'一十', u'十')

def _to_chinese8(num):
assert(num < _S8)
to4 = _to_chinese4
if num < _S4:
else:
mod = _S4
high, low = num / mod, num % mod
if low == 0:
else:
if low < _S4 / 10:
else:

def _to_chinese16(num):
assert(num < _S16)
to8 = _to_chinese8
mod = _S8
high, low = num / mod, num % mod
if low == 0:
else:
if low < _S8 / 10:
else:

def to_chinese(num):
if type(num) != types.Inwww.cppcns.comtType and type(num) != types.LongType:
raise NotIntegerError(u'%s is not a integer.' % num)
if num < _MIN or num > _MAX:
raise OutOfRangeError(u'%d out of range[%d, %d)' % (num, _MIN, _MAX))

if num < _S4:
return _to_编程客栈chinese4(num)
elif num < _S8:
return _to_chinese8(num)
else:
return _to_chinese16(num)

if __name__ == '__main__':
print to_chinese(9000)

```