# C++实现LeetCode(57.插入区间)

[LeetCode] 57. Insert Interval 插入区间 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

## [LeetCode] 57. Insert Interval 插入区间

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:

Input: intervals = [[1,3],[6,9]], newInterval = [2,5]

Output: [[1,5],[6,9]]

Example 2:

Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]

Output: [[1,2],[3,10],[12,16]]

Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10http://www.cppcns.com].

NOTE: input types have been changed on A编程客栈pril 15, 2019. Please reset to default code definition to get new method signature.

```class Solution {
public:
vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {
vector<vector<int>> res;
int n = intervals.size(), cur = 0;
while (cur < n && intervals[cur][1] < newInterval[0]) {
res.push_back(intervals[cur++]);
}
while (cur < n && intervals[cur][0] <= newInterval[1]) {
newInterval[0] = min(newInterval[0], intervals[cur][0]);
newInterval[1] = max(newInterval[1], intervals[cur][1]);
编程客栈 ++cur;
}
res.push_back(newInterval);
while (cur < n) {
res.push_back(intervals[cur++]);
}
return res;
}
};```

```class Solution {
public:
vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {
vector<vector<int>> res;
int n = intervals.size(), cur = 0;
for (int i = 0; i < n; ++i) {
if (intervals[i][1] < newInterval[0]) {
res.push_back(intervals[i]);
++cur;
} else if (intervals[i][0] > newInterval[1]) {
res.push_ba编程客栈ck(intervals[i]);
} else {
newInterval[0] = min(newInterval[0], intervals[i][0]);
newInterval[1] = max(newInterval[1], intervals[i][1]);
}
}
res.insert(res.begin() + cur, newInterval);
return res;
}
};```

```class Solution {
public:
vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {
vector<vector<int>> res;
int n = intervals.size(), cur = 0, i = 0;
while (i < n) {
if (intervals[i][1] < newInterval[0]) {
res.push_back(intervals[i]);
++cur;
} else if (intervals[i][0] > newInterval[1]) {
res.push_back(intervals[i]);
} else {
newInterval[0] = min(newInterval[0], intervals[i][0]);
newInterval[1] = max(newInterval[1], intervals[i][1]);
}
++i;
}
res.insert(res.begin() + cur, newInterval);
return res;
}
};```