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Ruby救援语法错误

运维开发网 https://www.qedev.com 2020-07-27 13:47 出处:网络 作者:运维开发网整理
我有以下代码行给出了一个错误: rescue Timeout::Error => e logs.puts("Rescued a timeout error...#{e}") email_ids_all.each do |email_delete| call= "/api/v2/emails/#{email_delete}/" uri= HTTParty.d
我有以下代码行给出了一个错误:

rescue Timeout::Error => e
    logs.puts("Rescued a timeout error...#{e}")
    email_ids_all.each do |email_delete|

      call= "/api/v2/emails/#{email_delete}/"
      uri= HTTParty.delete("https://www.surveys.com#{call}",
          :basic_auth => auth,
          :headers => { 'ContentType' => 'application/x-www-form-urlencoded', 'Content-Length' => "0" }
      )
      puts "Deleted email #{email_delete}".green
      log.puts("Deleted email #{email_delete}")
    end
    abort #abort entire script after deleting emails
  end

我收到的错误是这样的:

syntax error, unexpected keyword_rescue, expecting $end
  rescue Timeout::Error => e
        ^

基本上我只是尝试在脚本超时时运行API删除调用.虽然我在块中进行救援似乎并不重要,但我收到同样的错误.我在救援方法上的语法有什么问题?

使用救援的格式如下:

begin
  # Code you want to run that might raise exceptions
rescue YourExceptionClass => e
  # Code that runs in the case of YourExceptionClass
rescue ADifferentError => e
  # Code that runs in the case of ADifferentError
else
  # Code that runs if there was no error
ensure
  # Code that always runs at the end regardless of whether or not there was an error
end

这是一个有更多信息的问题:Begin, Rescue and Ensure in Ruby?.

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